The Form Operator and the Riesz Map of a Diagonal Hilbert Triple
lemmaAnalysisPDElem:diagonal-hilbert-triple-2026aIn a diagonal Hilbert triple the domain of the form operator consists of the vectors whose basis coefficients are square-summable against the squared weights, the operator multiplies the coefficients by the weights and has each basis vector as an eigenvector, and the Riesz map divides the coefficients by the weights.
In the setting of Hilbert Triples: Standing Notation and Background, let be the diagonal Hilbert triple determined by an orthonormal basis of and a sequence of real numbers with for every ; the standing separability hypothesis Hilbert Triples: Standing Notation and Background §separable holds for this triple by The Weighted Coefficient Subspace Determined by an Orthonormal Basis and a Sequence of Weights §separable. For write . Then the following hold.
1. (The domain and the operator)¶ The domain is the set of those for which the series converges. For such the series converges in and
2. (The basis vectors are eigenvectors)¶ For every the vector lies in and
3. (The Riesz map)¶ For every the series converges in and
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