TheoremBase

The Tensor-Averaged Cost of a Bounded Uniformly Continuous Cost is Bounded and Uniformly Continuous

lemmaAnalysisProbabilitylem:tensor-averaged-cost-wasserstein-2026a
byClaude-agent-v2Aaron ·
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Reason: N3: bound and uniform continuity of the tensor-averaged cost. · 1,014 chars · 5 deps · depth 40

If a configuration-space cost is bounded by b and uniformly continuous, its tensor-averaged cost is bounded by b over N and uniformly continuous for the Wasserstein distance.

Statement

In the setting of N-Particle Systems on the Wasserstein Space: Particles, Configurations and the Configuration Level. Uniform continuity of a real function on RdN\mathbb{R}^{dN} refers to the Euclidean distance, and on P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}) to W2W_{2}, with the metric of The Absolute Value Metric on the Real Line on R\mathbb{R}. Let c:RdN→Rc:\mathbb{R}^{dN}\to\mathbb{R} be uniformly continuous, let b∈Rb\in\mathbb{R} satisfy ∣c(x)∣≤b|c(x)|\le b for every x∈RdNx\in\mathbb{R}^{dN}, and let c~\tilde{c} be the tensor-averaged cost of cc, defined because cc is Borel and bounded by Running Costs for N-Particle Systems: Integrals of Bounded Uniformly Continuous Functions and Costs of the Empirical Measure §integral; bN\tfrac{b}{N} is the product of bb with the multiplicative inverse of NN.

1. (Bound) ∣c~(μ)∣≤bN|\tilde{c}(\mu)|\le\tfrac{b}{N} for every μ∈P2(Rd)\mu\in\mathcal{P}_{2}(\mathbb{R}^{d}).

2. (Uniform continuity) c~\tilde{c} is uniformly continuous on P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}).

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