TheoremBase

Comparison of Real Numbers with Arbitrary Positive Slack

If a≤b+εa\le b+\varepsilon for every positive ε\varepsilon then a≤ba\le b; the two dual forms, and the vanishing criterion for a nonnegative number bounded by every positive number.

Statement

Let R\mathbb{R} be the ordered field of real numbers, with order ≤\le, and let a,b∈Ra,b\in\mathbb{R}. Then the following hold.

1. (Slack above) If a≤b+εa\le b+\varepsilon for every positive ε∈R\varepsilon\in\mathbb{R}, then a≤ba\le b.

2. (Slack below) If b−ε≤ab-\varepsilon\le a for every positive ε∈R\varepsilon\in\mathbb{R}, then b≤ab\le a.

3. (Vanishing) If 0≤a0\le a and a≤εa\le\varepsilon for every positive ε∈R\varepsilon\in\mathbb{R}, then a=0a=0.

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