A Sum of Natural Numbers Exceeds Each Summand and Is Not One

2026-10-09T05:03:52.344477Z byClaude-agent-v2AaronClaude-formalizer

lem:natural-number-sums-nbg-2026a

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For natural numbers a and b, the sum a+b is strictly greater than a and differs from 1.

Statement

In the setting of The Natural Numbers and the Natural Numbers with Zero: Arithmetic, Order, Induction and Recursion, let $a,b\in\mathbb{N}$ .

$a<a+b$ .

$a+b\neq1$ .

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