The Penalty Function of a Hilbert Triple: Expansion Identities, Closed Sublevel Sets, Density and Local Bounds
lemmaAnalysisPDElem:hilbert-triple-penalty-2026aFor the penalty function h(x) = (1/2)|x|_V^2 on the small space of a Hilbert triple: h dominates (1/2)|x|_H^2, expands exactly to second order with gradient x in V and Ax in H, has sublevel sets closed in H (so h is lower semicontinuous on V for the metric of H), D(A) meets every open subset of H densely, and subtracting a positive multiple of h from a locally bounded function keeps it locally bounded on V.
In the setting of Hilbert Triples: Standing Notation and Background, let be the penalty function, . Semicontinuity of a function on , or on a subset of , is understood relative to that subset of the metric space , and closed superlevel sets are taken in the ambient space . For a nonempty subset of and a function , that is bounded above near each point of , or bounded below near each point of , refers to as a subset of the metric space . Claim 4 uses the standing separability of . Then the following hold.
1. (Nonnegativity and coercivity)¶ For every , ; and .
2. (Expansion in )¶ For all ,
3. (Expansion through the form operator)¶ For all and ,
4. (Closed sublevel sets)¶ The function , whose value at is , has closed superlevel sets in ; that is, for every the set is closed in . Consequently, whenever is a sequence in converging in to a point and satisfies for every , one has and ; and is lower semicontinuous on .
5. (Density of the domain in open sets)¶ Let be open in . Then for every and every real there is with . In particular, if is nonempty then so are and .
6. (Local bounds after penalisation)¶ Let be nonempty and open in , let , and let satisfy . If is bounded above near each point of , then the function whose value at is is bounded above near each point of . If is bounded below near each point of , then the function whose value at is is bounded below near each point of .
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