A regular function is twice differentiable along the modes with explicit mode derivatives; its free-field generator converges at every state to an explicit lattice sum; adding any multiple of the Gaussian penalty keeps the gradient energy convergent; the renormalised operator is defined at the penalty plus a regular function, in penalised form; and linear combinations of regular functions are regular.
In the setting of The Wick-Square Problem on the Torus: Standing Notation, let be regular, and fix one choice of data witnessing this: a curvature family with curvature bound and a weak part , for which the identity displayed in Regular Functions for the Wick-Square Problem: Diagonal Quadratics of Curvature of Order the Inverse Squared Weight, plus Twice Differentiable Functions on the Sobolev Space of Order -3 holds. Here is the inner product of the Sobolev space , and and are the gradient map and the Hessian map of ; is the unit family of the mode , which lies in by Lattice Sums of the Fourier Weights of the Torus, and the Negative Sobolev Norms as Lattice Sums §units, and by The Negative-Order Sobolev Spaces of the Torus are Hilbert Spaces: the Embedding of the Square-Integrable Classes, the Rescaled Trigonometric Basis, the Series Form of the Inner Product and the Inclusion of the Scale §inclusion, applied with and . Let be the Gaussian penalty; mode derivatives, and are those of Derivatives of a Function on the Sobolev Space of Order -1 along the Fourier Modes §derivatives, The Free-Field Generator with a Mode Cutoff §limit and The Gradient Energy with a Mode Cutoff §limit. Then the following hold.
1. (Mode derivatives) is twice differentiable along the modes, and for every and
2. (The generator converges) For every the families
are cube-summable, is defined at , and is the sum of their two lattice sums.
3. (The gradient energy converges) Let . Then is twice differentiable along the modes, and for every the family is cube-summable and is defined and equals its lattice sum.
4. (The renormalised operator) Let be a running cost, and let and be the domain and the renormalised operator for . Then for every one has and
5. (Linear combinations) Let be regular and . Then the pointwise combination is regular, and so is every constant function on .
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