In the setting of Second-Order Equations on Euclidean Open Sets and of Bounded Open Domain in Euclidean Space , whose notation, including that of Euclidean Space and Real Matrices: Standing Notation on which the former rests, is in force in the dimension n n n , a natural number with 1 ≤ n 1\le n 1 ≤ n , let T = { t ∈ R : 0 ≤ t } T=\{t\in\mathbb{R}:0\le t\} T = { t ∈ R : 0 ≤ t } and write 3 = 1 + 1 + 1 3=1+1+1 3 = 1 + 1 + 1 .
Two elementary consequences of the ordered field axioms are used freely below. First, multiplication by a nonnegative real number preserves ≤ \le ≤ : if a ≤ b a\le b a ≤ b and 0 ≤ λ 0\le\lambda 0 ≤ λ then either a = b a=b a = b , and the products are equal, or a < b a<b a < b , and then λ a ≤ λ b \lambda a\le\lambda b λa ≤ λb by claim 10 of Elementary Order Arithmetic in an Ordered Field when 0 < λ 0<\lambda 0 < λ , while λ = 0 \lambda=0 λ = 0 makes both products 0 0 0 . Second, if a ≤ b a\le b a ≤ b and 0 ≤ e 0\le e 0 ≤ e then a ≤ b + e a\le b+e a ≤ b + e , since b = b + 0 ≤ b + e b=b+0\le b+e b = b + 0 ≤ b + e by the compatibility of ≤ \le ≤ with addition and ≤ \le ≤ is transitive.
The data. Let b : Ω → R n b:\Omega\to\mathbb{R}^{n} b : Ω → R n be a function and let c ∈ R c\in\mathbb{R} c ∈ R be nonnegative, and assume
− c ∥ x − y ∥ 2 ≤ ( b ( x ) − b ( y ) ) ⋅ ( x − y ) for all x , y ∈ Ω , -c\lVert x-y\rVert^{2}\ \le\ \bigl(b(x)-b(y)\bigr)\cdot(x-y)\qquad\text{for all }x,y\in\Omega, − c ∥ x − y ∥ 2 ≤ ( b ( x ) − b ( y ) ) ⋅ ( x − y ) for all x , y ∈ Ω ,
where − c ∥ x − y ∥ 2 -c\lVert x-y\rVert^{2} − c ∥ x − y ∥ 2 is the additive inverse of c ∥ x − y ∥ 2 c\lVert x-y\rVert^{2} c ∥ x − y ∥ 2 .
Let ω c : T → R \omega_{c}:T\to\mathbb{R} ω c : T → R be given by ω c ( t ) = c t \omega_{c}(t)=ct ω c ( t ) = c t , a modulus of continuity by Linear Moduli of Continuity (i) . The formula
F ( x , r , p , X ) = b ( x ) ⋅ p F(x,r,p,X)=b(x)\cdot p F ( x , r , p , X ) = b ( x ) ⋅ p
defines a function F : Ω × R × R n × S ( n ) → R F:\Omega\times\mathbb{R}\times\mathbb{R}^{n}\times\mathcal{S}(n)\to\mathbb{R} F : Ω × R × R n × S ( n ) → R , that is, a second-order equation operator on Ω \Omega Ω .
The claim. (i) F F F and ω c \omega_{c} ω c satisfy the structure condition of the comparison principle for the Dirichlet problem .
Justification. Let x , y ∈ Ω x,y\in\Omega x , y ∈ Ω , let r ∈ R r\in\mathbb{R} r ∈ R , let α ∈ R \alpha\in\mathbb{R} α ∈ R be positive and let X , Y ∈ S ( n ) X,Y\in\mathcal{S}(n) X , Y ∈ S ( n ) satisfy the two-sided bound imposed by the structure condition, namely
− 3 α ( ∥ ξ ∥ 2 + ∥ η ∥ 2 ) ≤ ξ ⋅ ( X ξ ) − η ⋅ ( Y η ) ≤ 3 α ∥ ξ − η ∥ 2 for all ξ , η ∈ R n ; -3\alpha\bigl(\lVert\xi\rVert^{2}+\lVert\eta\rVert^{2}\bigr)\ \le\ \xi\cdot(X\xi)-\eta\cdot(Y\eta)\ \le\ 3\alpha\lVert\xi-\eta\rVert^{2}\qquad\text{for all }\xi,\eta\in\mathbb{R}^{n}; − 3 α ( ∥ ξ ∥ 2 + ∥ η ∥ 2 ) ≤ ξ ⋅ ( X ξ ) − η ⋅ ( Y η ) ≤ 3 α ∥ ξ − η ∥ 2 for all ξ , η ∈ R n ;
this bound plays no role below, since F F F does not depend on its matrix variable. Write p = α ( x − y ) p=\alpha(x-y) p = α ( x − y ) .
Step 1: an identity. By claim 3 of The Dot Product on R n \mathbb{R}^n R n Is Symmetric, Bilinear and Positive Definite , applied twice, and the field identity s − t = − ( t − s ) s-t=-(t-s) s − t = − ( t − s ) ,
F ( y , r , p , Y ) − F ( x , r , p , X ) = b ( y ) ⋅ p − b ( x ) ⋅ p = ( b ( y ) − b ( x ) ) ⋅ p , F(y,r,p,Y)-F(x,r,p,X)=b(y)\cdot p-b(x)\cdot p=\bigl(b(y)-b(x)\bigr)\cdot p, F ( y , r , p , Y ) − F ( x , r , p , X ) = b ( y ) ⋅ p − b ( x ) ⋅ p = ( b ( y ) − b ( x ) ) ⋅ p ,
and
( b ( y ) − b ( x ) ) ⋅ ( x − y ) = b ( y ) ⋅ ( x − y ) − b ( x ) ⋅ ( x − y ) = − ( ( b ( x ) − b ( y ) ) ⋅ ( x − y ) ) . \bigl(b(y)-b(x)\bigr)\cdot(x-y)=b(y)\cdot(x-y)-b(x)\cdot(x-y)=-\Bigl(\bigl(b(x)-b(y)\bigr)\cdot(x-y)\Bigr). ( b ( y ) − b ( x ) ) ⋅ ( x − y ) = b ( y ) ⋅ ( x − y ) − b ( x ) ⋅ ( x − y ) = − ( ( b ( x ) − b ( y ) ) ⋅ ( x − y ) ) .
Since p = α ( x − y ) p=\alpha(x-y) p = α ( x − y ) , claim 5 of The Dot Product on R n \mathbb{R}^n R n Is Symmetric, Bilinear and Positive Definite gives ( b ( y ) − b ( x ) ) ⋅ p = α ( ( b ( y ) − b ( x ) ) ⋅ ( x − y ) ) \bigl(b(y)-b(x)\bigr)\cdot p=\alpha\Bigl(\bigl(b(y)-b(x)\bigr)\cdot(x-y)\Bigr) ( b ( y ) − b ( x ) ) ⋅ p = α ( ( b ( y ) − b ( x ) ) ⋅ ( x − y ) ) .
Step 2: the drift hypothesis. Applying claim 4 of Elementary Order Arithmetic in an Ordered Field to the hypothesis − c ∥ x − y ∥ 2 ≤ ( b ( x ) − b ( y ) ) ⋅ ( x − y ) -c\lVert x-y\rVert^{2}\le\bigl(b(x)-b(y)\bigr)\cdot(x-y) − c ∥ x − y ∥ 2 ≤ ( b ( x ) − b ( y ) ) ⋅ ( x − y ) and using − ( − c ∥ x − y ∥ 2 ) = c ∥ x − y ∥ 2 -\bigl(-c\lVert x-y\rVert^{2}\bigr)=c\lVert x-y\rVert^{2} − ( − c ∥ x − y ∥ 2 ) = c ∥ x − y ∥ 2 ,
− ( ( b ( x ) − b ( y ) ) ⋅ ( x − y ) ) ≤ c ∥ x − y ∥ 2 , -\Bigl(\bigl(b(x)-b(y)\bigr)\cdot(x-y)\Bigr)\ \le\ c\lVert x-y\rVert^{2}, − ( ( b ( x ) − b ( y ) ) ⋅ ( x − y ) ) ≤ c ∥ x − y ∥ 2 ,
so by Step 1, ( b ( y ) − b ( x ) ) ⋅ ( x − y ) ≤ c ∥ x − y ∥ 2 \bigl(b(y)-b(x)\bigr)\cdot(x-y)\le c\lVert x-y\rVert^{2} ( b ( y ) − b ( x ) ) ⋅ ( x − y ) ≤ c ∥ x − y ∥ 2 .
Step 3: conclusion. Multiplying the inequality of Step 2 by the nonnegative α \alpha α and using Step 1,
F ( y , r , p , Y ) − F ( x , r , p , X ) ≤ α ( c ∥ x − y ∥ 2 ) = c ( α ∥ x − y ∥ 2 ) , F(y,r,p,Y)-F(x,r,p,X)\ \le\ \alpha\bigl(c\lVert x-y\rVert^{2}\bigr)=c\bigl(\alpha\lVert x-y\rVert^{2}\bigr), F ( y , r , p , Y ) − F ( x , r , p , X ) ≤ α ( c ∥ x − y ∥ 2 ) = c ( α ∥ x − y ∥ 2 ) ,
the last equality by the commutativity and associativity of multiplication in R \mathbb{R} R . Put t = α ∥ x − y ∥ 2 + ∥ x − y ∥ t=\alpha\lVert x-y\rVert^{2}+\lVert x-y\rVert t = α ∥ x − y ∥ 2 + ∥ x − y ∥ . By claim 1 of Properties of the Euclidean Norm on R n \mathbb{R}^n R n : Square, Distance, Vanishing, Coordinate Bounds, Homogeneity, Triangle Inequalities and Expansion of a Square the number ∥ x − y ∥ \lVert x-y\rVert ∥ x − y ∥ is nonnegative, hence so is ∥ x − y ∥ 2 \lVert x-y\rVert^{2} ∥ x − y ∥ 2 by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field , and therefore 0 ≤ α ∥ x − y ∥ 2 0\le\alpha\lVert x-y\rVert^{2} 0 ≤ α ∥ x − y ∥ 2 ; consequently α ∥ x − y ∥ 2 ≤ t \alpha\lVert x-y\rVert^{2}\le t α ∥ x − y ∥ 2 ≤ t and 0 ≤ t 0\le t 0 ≤ t , so t ∈ T t\in T t ∈ T . Multiplying α ∥ x − y ∥ 2 ≤ t \alpha\lVert x-y\rVert^{2}\le t α ∥ x − y ∥ 2 ≤ t by the nonnegative c c c and using transitivity,
F ( y , r , α ( x − y ) , Y ) − F ( x , r , α ( x − y ) , X ) ≤ c t = ω c ( α ∥ x − y ∥ 2 + ∥ x − y ∥ ) , F\bigl(y,r,\alpha(x-y),Y\bigr)-F\bigl(x,r,\alpha(x-y),X\bigr)\ \le\ ct=\omega_{c}\bigl(\alpha\lVert x-y\rVert^{2}+\lVert x-y\rVert\bigr), F ( y , r , α ( x − y ) , Y ) − F ( x , r , α ( x − y ) , X ) ≤ c t = ω c ( α ∥ x − y ∥ 2 + ∥ x − y ∥ ) ,
which is the inequality required by the structure condition.
The hypothesis in other words. For x , y ∈ Ω x,y\in\Omega x , y ∈ Ω let b ( x ) + c x b(x)+cx b ( x ) + c x denote the sum of b ( x ) b(x) b ( x ) with the scalar multiple c x cx c x . Then ( b ( x ) + c x ) − ( b ( y ) + c y ) = ( b ( x ) − b ( y ) ) + c ( x − y ) \bigl(b(x)+cx\bigr)-\bigl(b(y)+cy\bigr)=\bigl(b(x)-b(y)\bigr)+c(x-y) ( b ( x ) + c x ) − ( b ( y ) + cy ) = ( b ( x ) − b ( y ) ) + c ( x − y ) in R n \mathbb{R}^{n} R n , so by claims 2 and 4 of The Dot Product on R n \mathbb{R}^n R n Is Symmetric, Bilinear and Positive Definite and claim 1 of Properties of the Euclidean Norm on R n \mathbb{R}^n R n : Square, Distance, Vanishing, Coordinate Bounds, Homogeneity, Triangle Inequalities and Expansion of a Square ,
( ( b ( x ) + c x ) − ( b ( y ) + c y ) ) ⋅ ( x − y ) = ( b ( x ) − b ( y ) ) ⋅ ( x − y ) + c ∥ x − y ∥ 2 , \Bigl(\bigl(b(x)+cx\bigr)-\bigl(b(y)+cy\bigr)\Bigr)\cdot(x-y)=\bigl(b(x)-b(y)\bigr)\cdot(x-y)+c\lVert x-y\rVert^{2}, ( ( b ( x ) + c x ) − ( b ( y ) + cy ) ) ⋅ ( x − y ) = ( b ( x ) − b ( y ) ) ⋅ ( x − y ) + c ∥ x − y ∥ 2 ,
and adding c ∥ x − y ∥ 2 c\lVert x-y\rVert^{2} c ∥ x − y ∥ 2 to both sides of the drift hypothesis shows that this quantity is nonnegative. The hypothesis therefore says exactly that the map x ↦ b ( x ) + c x x\mapsto b(x)+cx x ↦ b ( x ) + c x is monotone on Ω \Omega Ω .