In the setting of Second-Order Equations on Euclidean Open Sets and of Bounded Open Domain in Euclidean Space, whose notation, including that of Real Matrices, Symmetric Matrices and the Semidefinite Ordering: Standing Notation on which the former rests, is in force in the dimension n, a natural number with 1≤n, let T={t∈R:0≤t} and write 3=1+1+1.
Two elementary consequences of the ordered field axioms are used freely below. First, multiplication by a nonnegative real number preserves ≤: if a≤b and 0≤λ then either a=b, and the products are equal, or a<b, and then λa≤λb by claim 10 of Elementary Order Arithmetic in an Ordered Field when 0<λ, while λ=0 makes both products 0. Second, if a≤b and 0≤e then a≤b+e, since b=b+0≤b+e by the compatibility of ≤ with addition and ≤ is transitive.
The data. Let b:Ω→Rn be a function and let c∈R be nonnegative, and assume
−c∥x−y∥2 ≤ (b(x)−b(y))⋅(x−y)for all x,y∈Ω,
where −c∥x−y∥2 is the additive inverse of c∥x−y∥2.
Let ωc:T→R be given by ωc(t)=ct, a modulus of continuity by Linear Moduli of Continuity §modulus. The formula
F(x,r,p,X)=b(x)⋅p
defines a function F:Ω×R×Rn×S(n)→R, that is, a second-order equation operator on Ω.
The claim.¶ F and ωc satisfy the structure condition of the comparison principle for the Dirichlet problem.
Justification. Let x,y∈Ω, let r∈R, let α∈R be positive and let X,Y∈S(n) satisfy the two-sided bound imposed by the structure condition, namely
−3α(∥ξ∥2+∥η∥2) ≤ ξ⋅(Xξ)−η⋅(Yη) ≤ 3α∥ξ−η∥2for all ξ,η∈Rn;
this bound plays no role below, since F does not depend on its matrix variable. Write p=α(x−y).
Step 1: an identity. By claim 3 of Bilinearity and Symmetry of the Dot Product on Rn, applied twice, and the field identity s−t=−(t−s),
F(y,r,p,Y)−F(x,r,p,X)=b(y)⋅p−b(x)⋅p=(b(y)−b(x))⋅p,
and
(b(y)−b(x))⋅(x−y)=b(y)⋅(x−y)−b(x)⋅(x−y)=−((b(x)−b(y))⋅(x−y)).
Since p=α(x−y), claim 5 of Bilinearity and Symmetry of the Dot Product on Rn gives (b(y)−b(x))⋅p=α((b(y)−b(x))⋅(x−y)).
Step 2: the drift hypothesis. Applying claim 4 of Elementary Order Arithmetic in an Ordered Field to the hypothesis −c∥x−y∥2≤(b(x)−b(y))⋅(x−y) and using −(−c∥x−y∥2)=c∥x−y∥2,
−((b(x)−b(y))⋅(x−y)) ≤ c∥x−y∥2,
so by Step 1, (b(y)−b(x))⋅(x−y)≤c∥x−y∥2.
Step 3: conclusion. Multiplying the inequality of Step 2 by the nonnegative α and using Step 1,
F(y,r,p,Y)−F(x,r,p,X) ≤ α(c∥x−y∥2)=c(α∥x−y∥2),
the last equality by the commutativity and associativity of multiplication in R. Put t=α∥x−y∥2+∥x−y∥. By claim 1 of Elementary Properties of the Euclidean Norm on Rn the number ∥x−y∥ is nonnegative, hence so is ∥x−y∥2 by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field, and therefore 0≤α∥x−y∥2; consequently α∥x−y∥2≤t and 0≤t, so t∈T. Multiplying α∥x−y∥2≤t by the nonnegative c and using transitivity,
F(y,r,α(x−y),Y)−F(x,r,α(x−y),X) ≤ ct=ωc(α∥x−y∥2+∥x−y∥),
which is the inequality required by the structure condition.
The hypothesis in other words. For x,y∈Ω let b(x)+cx denote the sum of b(x) with the scalar multiple cx. Then (b(x)+cx)−(b(y)+cy)=(b(x)−b(y))+c(x−y) in Rn, so by claims 2 and 4 of Bilinearity and Symmetry of the Dot Product on Rn and claim 1 of Elementary Properties of the Euclidean Norm on Rn,
((b(x)+cx)−(b(y)+cy))⋅(x−y)=(b(x)−b(y))⋅(x−y)+c∥x−y∥2,
and adding c∥x−y∥2 to both sides of the drift hypothesis shows that this quantity is nonnegative. The hypothesis therefore says exactly that the map x↦b(x)+cx is monotone on Ω.