TheoremBase

Inner and Outer Regularity of a Finite Borel Measure on a Metric Space, and Lipschitz Approximation of Indicators

Every Borel set is squeezed between a closed set and an open set of nearly the same finite Borel measure, so the measure is the supremum of the measures of the closed subsets and the infimum of those of the open supersets; consequently the indicator of a Borel set is approximated in mean square by Lipschitz functions with values in the unit interval.

Statement

Let (X,d)(X,d) be a metric space with XX nonempty, let Td\mathcal{T}_{d} be its topology of open subsets, and let B(X)\mathcal{B}(X) be its Borel σ\sigma-algebra; by claim 1 of Borel Measurability and Bounded Integration on a Metric Space every open subset of (X,d)(X,d) and every closed subset of (X,Td)(X,\mathcal{T}_{d}) belongs to B(X)\mathcal{B}(X). Let μ\mu be a Borel measure on (X,d)(X,d) with μ(X)<∞\mu(X)<\infty, and regard R\mathbb{R} as a metric space with the absolute-value metric, its Borel σ\sigma-algebra being written B(R)\mathcal{B}(\mathbb{R}). For B∈B(X)B\in\mathcal{B}(X) let 1B:X→R\mathbf{1}_{B}:X\to\mathbb{R} be the indicator of BB.

1. (Approximation from inside and from outside) Let B∈B(X)B\in\mathcal{B}(X) and let ε\varepsilon be a positive real number. Then there are a set FF closed in (X,Td)(X,\mathcal{T}_{d}) and a set UU open in (X,d)(X,d) with F⊆B⊆UF\subseteq B\subseteq U and

μ(U∖F)≤ε.\mu(U\setminus F)\le\varepsilon .

2. (Inner regularity by closed sets) Let B∈B(X)B\in\mathcal{B}(X). Then the set of real numbers {μ(F):F⊆B and F is closed in (X,Td)}\{\mu(F):F\subseteq B\text{ and }F\text{ is closed in }(X,\mathcal{T}_{d})\} is nonempty and bounded above, and μ(B)\mu(B) is its least upper bound.

3. (Outer regularity by open sets) Let B∈B(X)B\in\mathcal{B}(X). Then the set of real numbers {μ(U):B⊆U and U is open in (X,d)}\{\mu(U):B\subseteq U\text{ and }U\text{ is open in }(X,d)\} is nonempty and bounded below, and μ(B)\mu(B) is its greatest lower bound.

4. (Lipschitz approximation of an indicator) Let B∈B(X)B\in\mathcal{B}(X) and let ε\varepsilon be a positive real number. Then there are a map h:X→Rh:X\to\mathbb{R} that is Lipschitz with a constant and satisfies 0≤h(x)≤10\le h(x)\le1 for every x∈Xx\in X, and a set N∈B(X)N\in\mathcal{B}(X) with μ(N)≤ε\mu(N)\le\varepsilon, such that

h(x)=1B(x)for every x∈X∖N.h(x)=\mathbf{1}_{B}(x)\qquad\text{for every }x\in X\setminus N .

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