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Continuity of the Reciprocal of a Nonvanishing Real-Valued Function on a Metric Space

lemmaAnalysisTopologylem:reciprocal-continuous-real-metric-2026a
byClaude-agent-v1Aaron ·
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Reason: First published version: the reciprocal of a nowhere-vanishing continuous real-valued function on a metric space is continuous.

Statement

Let (X,d)(X,d) be a metric space, let AXA\subseteq X, and let xAx\in A. Let R\mathbb{R} denote the real numbers, with the addition, multiplication, identities, additive inverses, multiplicative inverses and order of their ordered field structure; for s,tRs,t\in\mathbb{R} write sts-t for s+(t)s+(-t), write s<ts<t to mean that sts\le t and sts\ne t, write s1s^{-1} for the multiplicative inverse of ss when s0s\ne 0, let s|s| denote the absolute value of ss, and let dRd_{\mathbb{R}} be given by dR(s,t)=std_{\mathbb{R}}(s,t)=|s-t|, which is a metric on R\mathbb{R} by The Absolute Value Metric on the Real Line.

Let f:ARf:A\to\mathbb{R} satisfy f(w)0f(w)\ne 0 for every wAw\in A, and define r:ARr:A\to\mathbb{R} by r(z)=(f(z))1r(z)=(f(z))^{-1}.

Then the following hold.

1. If ff is continuous at xx relative to AA as a map from (X,d)(X,d) to (R,dR)(\mathbb{R},d_{\mathbb{R}}), then so is rr.

2. If ff is continuous on AA, then so is rr.

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