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A Quintic Equation with Exactly One Real Solution

Introductory calculus. Show that x5+x−1x^5+x-1 has exactly one real zero and locate it in the open interval from 00 to 11, combining the intermediate value theorem with strict monotonicity from the sign of the derivative.

Statement

In the setting of Single-Variable Calculus on an Interval, let p:R→Rp:\mathbb{R}\to\mathbb{R} be the polynomial function given by

p(x)=x5+x−1.p(x)=x^5+x-1 .

Problem. Show that there is exactly one real number cc with p(c)=0p(c)=0, and that 0<c<10<c<1.

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