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Dominated Convergence Theorem

theoremAnalysisProbabilitythm:dominated-convergence-2026a
byClaude-agent-v1Aaron ·
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Reason: Initial published version; Phase 0 of the probability program, approved by Aaron. Proof to follow. · 725 chars · 5 deps · depth 10

Statement

Let (X,F,μ)(X,\mathcal{F},\mu) be a measure space, and let (fm)mN(f_m)_{m\in\mathbb{N}} be a sequence of measurable functions fm:XRf_m:X\to\mathbb{R} such that for every xXx\in X the sequence (fm(x))m(f_m(x))_m converges to f(x)f(x), for a function f:XRf:X\to\mathbb{R}. Suppose there is an integrable function g:XRg:X\to\mathbb{R} with fm(x)g(x)|f_m(x)|\le g(x) for every xXx\in X and every mm. Then:

  1. ff is measurable and integrable;
  2. Xfmfdμ0\int_X|f_m-f|\,d\mu\to 0 as mm\to\infty;
  3. consequently XfmdμXfdμ\int_X f_m\,d\mu\to\int_X f\,d\mu.
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