TheoremBase

Dominated Convergence Theorem

If measurable real maps converge pointwise and are dominated by one integrable map, then the limit and all terms are integrable, the integrals of the distances to the limit tend to zero, and the integrals converge to the integral of the limit.

Statement

In the setting of Measurable Functions and the Lebesgue Integral: Notation, let (X,F,μ)(X,\mathcal{F},\mu) be a measure space. Let (fm)m∈N(f_{m})_{m\in\mathbb{N}} be a sequence in Meas(X,F;R,B(R))\mathrm{Meas}(X,\mathcal{F};\mathbb{R},\mathcal{B}(\mathbb{R})), that is, of measurable functions fm:X→Rf_{m}:X\to\mathbb{R}, and let f:X→Rf:X\to\mathbb{R} be a function with

fm(x)→f(x)for every x∈X.f_{m}(x)\to f(x)\qquad\text{for every }x\in X .

Let g∈L1(μ)g\in\mathcal{L}^{1}(\mu) satisfy ∣fm(x)∣≤g(x)|f_{m}(x)|\le g(x) for every m∈Nm\in\mathbb{N} and every x∈Xx\in X.

Integrability. f∈L1(μ)f\in\mathcal{L}^{1}(\mu), and fm∈L1(μ)f_{m}\in\mathcal{L}^{1}(\mu) for every m∈Nm\in\mathbb{N}.

Convergence in mean. ∣fm−f∣∈L1(μ)|f_{m}-f|\in\mathcal{L}^{1}(\mu) for every m∈Nm\in\mathbb{N}, and, for the integrals of these elements of L1(μ)\mathcal{L}^{1}(\mu),

∫X∣fm−f∣ dμ→0.\int_{X}|f_{m}-f|\,d\mu\to0 .

Convergence of the integrals.

∫Xfm dμ→∫Xf dμ.\int_{X}f_{m}\,d\mu\to\int_{X}f\,d\mu .

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