TheoremBase

Lambda-Displacement Convexity of a Noise Penalty Pair

A noise penalty pair is lambda-displacement convex if the penalty lies above its first-order expansion along every noise-optimal coupling out of a score-domain measure, with a lambda/2 times noise-cost correction.

Statement

In the setting of First-Order Equations on the Noise Wasserstein Space Relative to a Noise Penalty Pair: Standing Notation, let (D,DΣ,E,Σ)(\mathcal{D},\mathcal{D}_{\Sigma},\mathcal{E},\Sigma) be a noise penalty pair on Pρa\mathcal{P}^{a}_{\rho} and let λ∈R\lambda\in\mathbb{R}. For μ∈DΣ\mu\in\mathcal{D}_{\Sigma} one has μ∈D\mu\in\mathcal{D}, so that E(μ)\mathcal{E}(\mu) is a real number, and the score Σ(μ)\Sigma(\mu) lies in TμaT^{a}_{\mu}, hence in L2(μ;Xa)L^{2}(\mu;X^{a}), both by Noise Penalty Pairs on the Noise Wasserstein Space: the Penalty, Its Score, and Their Domains §pair. For ν∈D\nu\in\mathcal{D} the ordered pair (μ,ν)(\mu,\nu) is noise-connected by The Noise Wasserstein Distance is a Metric on the Measures Noise-Connected to the Reference Measure: Existence of Noise-Optimal Couplings, Comparison with the Quadratic Wasserstein Distance and Lower Semicontinuity §connected, since μ,ν∈D⊆Pρa\mu,\nu\in\mathcal{D}\subseteq\mathcal{P}^{a}_{\rho} by Noise Penalty Pairs on the Noise Wasserstein Space: the Penalty, Its Score, and Their Domains §pair, so that noise-optimal couplings π∈Πa(μ,ν)\pi\in\Pi^{a}(\mu,\nu) are defined, and for such π\pi the noise displacement pairing Ja(Σ(μ),π)\mathcal{J}^{a}(\Sigma(\mu),\pi) and the noise cost Ia(π)I^{a}(\pi) are the real numbers of First-Order Equations on the Noise Wasserstein Space Relative to a Noise Penalty Pair: Standing Notation §couplings.

(λ\lambda-displacement convexity) The noise penalty pair (D,DΣ,E,Σ)(\mathcal{D},\mathcal{D}_{\Sigma},\mathcal{E},\Sigma) is λ\lambda-displacement convex if

E(μ)+Ja(Σ(μ),π)+λ2 Ia(π) ≤ E(ν)\mathcal{E}(\mu)+\mathcal{J}^{a}(\Sigma(\mu),\pi)+\tfrac{\lambda}{2}\,I^{a}(\pi)\ \le\ \mathcal{E}(\nu)

for every μ∈DΣ\mu\in\mathcal{D}_{\Sigma}, every ν∈D\nu\in\mathcal{D} and every noise-optimal coupling π∈Πa(μ,ν)\pi\in\Pi^{a}(\mu,\nu). It is displacement convex if it is 00-displacement convex.

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