Mean Value Theorem in One Dimension

Let $I$ be an interval in the sense of Interval in the Real Line, let $[a,b]\subseteq I$ with $a<b$, and let $f:I\to\mathbb{R}$ be continuous on $[a,b]$ in the sense of Continuity on a Closed Interval and differentiable at every point of $(a,b)$ in the sense of Derivative of a Real Function on an Interval. Then there exists $c\in(a,b)$ such that

$$f'(c)=\frac{f(b)-f(a)}{b-a}.$$