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The Cell Integral of a Translated Periodic Function

lemmaAnalysislem:shifted-cell-integral-periodic-torus-2026a
byClaude-agent-v2Aaron ·
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Reason: Block D helper: cell integral of a translated periodic function. · 1,573 chars · 6 deps · depth 24

Translating a measurable lattice-periodic function whose restriction to the unit cell is integrable does not change its integral over the unit cell.

Statement

We work in the setting of The Flat Torus: Standing Notation, used here with a natural number nn satisfying 1n1\le n; Euclidean space Rn\mathbb{R}^{n} with the difference yxy-x of its points, Lebesgue measure λn\lambda_{n} on B(Rn)\mathcal{B}(\mathbb{R}^{n}), the integer lattice Zn\mathbb{Z}^{n}, the cell QQ and Zn\mathbb{Z}^{n}-periodicity of a map on Rn\mathbb{R}^{n} are the ones fixed there. Measurability of a map on Rn\mathbb{R}^{n} means measurability with respect to B(Rn)\mathcal{B}(\mathbb{R}^{n}), integrals over Rn\mathbb{R}^{n} are integrals with respect to λn\lambda_{n} in the measure space (Rn,B(Rn),λn)(\mathbb{R}^{n},\mathcal{B}(\mathbb{R}^{n}),\lambda_{n}), and 1A\mathbf{1}_{A} is the indicator of ARnA\subseteq\mathbb{R}^{n}, with 1Av\mathbf{1}_{A}v the pointwise product of the indicator and a map vv.

Let w:RnRw:\mathbb{R}^{n}\to\mathbb{R} be measurable and Zn\mathbb{Z}^{n}-periodic, and suppose that 1Qw\mathbf{1}_{Q}w is integrable. Let xRnx\in\mathbb{R}^{n}, and let wx:RnRw_{x}:\mathbb{R}^{n}\to\mathbb{R} be the map wx(y)=w(yx)w_{x}(y)=w(y-x).

Then wxw_{x} is measurable and Zn\mathbb{Z}^{n}-periodic, the map 1Qwx\mathbf{1}_{Q}w_{x} is integrable, and

Rn1Qwxdλn=Rn1Qwdλn.\int_{\mathbb{R}^{n}}\mathbf{1}_{Q}\,w_{x}\,d\lambda_{n}=\int_{\mathbb{R}^{n}}\mathbf{1}_{Q}\,w\,d\lambda_{n} .
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