TheoremBase

Independence of σ-Algebras: π-Systems, Grouping and Pairs

Subfamilies of independent families are independent; independent π-systems generate independent σ-algebras; σ-algebras generated by disjoint groups of an independent family are independent; and independence of two σ-algebras agrees with independence of the two-member family.

Statement

In the setting of Probability Spaces: Notation, let JJ be a set.

Subfamilies. Let (Cj)j∈J(\mathcal{C}_{j})_{j\in J} be an independent family of subsets of F\mathcal{F}, let J′⊆JJ'\subseteq J, and for j∈J′j\in J' let Dj⊆Cj\mathcal{D}_{j}\subseteq\mathcal{C}_{j}. Then the family (Dj)j∈J′(\mathcal{D}_{j})_{j\in J'} is independent.

Independent π\pi-systems generate independent σ\sigma-algebras. Let (Cj)j∈J(\mathcal{C}_{j})_{j\in J} be an independent family of π\pi-systems on Ω\Omega contained in F\mathcal{F}. Then the family (σ(Cj))j∈J(\sigma(\mathcal{C}_{j}))_{j\in J} (Closure Properties of σ-Algebras, Intersections and Traces of σ-Algebras, and the Generated σ-Algebra (iii), Closure Properties of σ-Algebras, Intersections and Traces of σ-Algebras, and the Generated σ-Algebra (iv)) is independent.

Grouping. Let (Gj)j∈J(\mathcal{G}_{j})_{j\in J} be an independent family of σ\sigma-algebras on Ω\Omega contained in F\mathcal{F}, let KK be a set and let (Jk)k∈K(J_{k})_{k\in K} be a family of pairwise disjoint subsets of JJ. For k∈Kk\in K let

Hk=σ(⋃j∈JkGj).\mathcal{H}_{k}=\sigma\Bigl(\bigcup_{j\in J_{k}}\mathcal{G}_{j}\Bigr).

Then the family (Hk)k∈K(\mathcal{H}_{k})_{k\in K} is independent.

Two σ\sigma-algebras as a family. Let G\mathcal{G} and H\mathcal{H} be σ\sigma-algebras on Ω\Omega contained in F\mathcal{F}. Then G\mathcal{G} and H\mathcal{H} are independent if and only if the family (Gk)k∈[2](\mathcal{G}_{k})_{k\in[2]} with G1=G\mathcal{G}_{1}=\mathcal{G} and G2=H\mathcal{G}_{2}=\mathcal{H} is independent.

Two independent π\pi-systems. Let C\mathcal{C} and D\mathcal{D} be π\pi-systems on Ω\Omega contained in F\mathcal{F} with

P(C∩D)=P(C) P(D)(C∈C, D∈D).P(C\cap D)=P(C)\,P(D)\qquad(C\in\mathcal{C},\ D\in\mathcal{D}).

Then σ(C)\sigma(\mathcal{C}) and σ(D)\sigma(\mathcal{D}) are independent.

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