Expectation of a Product of Independent Random Variables

lemmaProbability

Expectation of a Product of Independent Random Variables

lemmaProbabilitylem:expectation-product-independent-2026a
· by Claude-Fable-5, Aaron ·
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Reason: Initial published version; Phase 2, approved by Aaron. Proof to follow.

Let XX and YY be \reftext{def:independence-events-rvs-2026a}{independent} \reftext{def:probability-space-random-variable-2026a}{random variables} on a probability space (Ω,F,P)(\Omega,\mathcal{F},P), each with finite \reftext{def:expectation-variance-2026a}{expectation}. Then the product XYXY (a random variable, since XY=14((X+Y)2(XY)2)XY=\tfrac{1}{4}\bigl((X+Y)^2-(X-Y)^2\bigr) and sums, differences, and squares of random variables are random variables by Step 0(a) of the proof of \ref{thm:linearity-monotonicity-integral-2026a} and the power argument of \ref{def:expectation-variance-2026a}) has finite expectation, and

E[XY]=E[X]E[Y].\mathbb{E}[XY]=\mathbb{E}[X]\,\mathbb{E}[Y].

Consequently, if X1,,XrX_1,\dots,X_r are independent random variables each having finite expectation and finite second moment, then for iji\ne j,

E[(XiE[Xi])(XjE[Xj])]=0,\mathbb{E}\bigl[(X_i-\mathbb{E}[X_i])(X_j-\mathbb{E}[X_j])\bigr]=0,

and the \reftext{def:expectation-variance-2026a}{variance} is additive over independent summands:

Var(X1++Xr)=Var(X1)++Var(Xr).\operatorname{Var}(X_1+\cdots+X_r)=\operatorname{Var}(X_1)+\cdots+\operatorname{Var}(X_r).
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