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Integrals of Finite Sums of Nonnegative Functions, and Constant Multiples of a Measure

The integral of a finite sum of nonnegative measurable functions is the sum of their integrals; and a constant multiple cμ of a measure is a measure, the measure with constant density c, against which integrals are c times the integrals against μ.

Statement

In the setting of Measurable Functions and the Lebesgue Integral: Standing Notation, let (X,F,μ)(X,\mathcal{F},\mu) be a measure space. Sums and products in [0,∞][0,\infty] are those of Addition and Multiplication on [0,∞] (i) and Addition and Multiplication on [0,∞] (ii), and sums over a finite set of elements of [0,∞][0,\infty] are as in Sums and Products over a Finite Set and over an Interval (v), ([0,∞],+,0)([0,\infty],+,0) being a commutative monoid by Arithmetic in [0,∞]: Monoid Laws, Distributivity, Monotonicity and Cancellation (i). Let c∈Rc\in\mathbb{R} with c≥0c\ge0, and let cμ:F→[0,∞]c\mu:\mathcal{F}\to[0,\infty] be the function

(cμ)(A)=c⋅μ(A)(A∈F).(c\mu)(A)=c\cdot\mu(A)\qquad(A\in\mathcal{F}).

Finite sums. Let II be a finite set and Φ:I×X→[0,∞]\Phi:I\times X\to[0,\infty] a function such that, for every i∈Ii\in I, the function fi=Φ(i,⋅)f_{i}=\Phi(i,\cdot), x↦Φ(i,x)x\mapsto\Phi(i,x), lies in M+(X,F)\mathcal{M}^{+}(X,\mathcal{F}). Let ∑i∈Ifi:X→[0,∞]\sum_{i\in I}f_{i}:X\to[0,\infty] be the function with

(∑i∈Ifi)(x)=∑i∈IΦ(i,x)(x∈X).\Bigl(\sum_{i\in I}f_{i}\Bigr)(x)=\sum_{i\in I}\Phi(i,x)\qquad(x\in X).

Then ∑i∈Ifi∈M+(X,F)\sum_{i\in I}f_{i}\in\mathcal{M}^{+}(X,\mathcal{F}) and

∫X∑i∈Ifi dμ=∑i∈I∫Xfi dμ.\int_{X}\sum_{i\in I}f_{i}\,d\mu=\sum_{i\in I}\int_{X}f_{i}\,d\mu .

Constant multiples of a measure. cμc\mu is a measure on (X,F)(X,\mathcal{F}), and cμ=gμc\mu=g\mu, the measure with density gg with respect to μ\mu, for the constant function g:X→[0,∞]g:X\to[0,\infty] with value cc.

Integrals of nonnegative functions against cμc\mu. For every f∈M+(X,F)f\in\mathcal{M}^{+}(X,\mathcal{F}),

∫Xf d(cμ)=c∫Xf dμ.\int_{X}f\,d(c\mu)=c\int_{X}f\,d\mu .

Integrability with respect to cμc\mu. Let c>0c>0 and let f:X→Rf:X\to\mathbb{R} be measurable. Then f∈L1(cμ)f\in\mathcal{L}^{1}(c\mu) if and only if f∈L1(μ)f\in\mathcal{L}^{1}(\mu), and in that case

∫Xf d(cμ)=c∫Xf dμ.\int_{X}f\,d(c\mu)=c\int_{X}f\,d\mu .

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