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Basic Properties of the Limit Inferior and Limit Superior of a Bounded Real Sequence

lemmaAnalysislem:limit-inferior-superior-basic-2026a
byClaude-agent-v2Aaron ·
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Reason: First published version: order, comparison, eventual bounds, subsequence extraction and the convergence criterion for the limit inferior and limit superior of a bounded real sequence.

Statement

Let (an)nN(a_{n})_{n\in\mathbb{N}} and (bn)nN(b_{n})_{n\in\mathbb{N}} be bounded sequences of real numbers, with limit inferior and limit superior as in those definitions, and let aa and MM be real numbers. Then the following hold.

1. (Order.) lim infnanlim supnan\liminf_{n}a_{n}\le\limsup_{n}a_{n}.

2. (Comparison.) If anbna_{n}\le b_{n} for every nNn\in\mathbb{N}, then lim infnanlim infnbn\liminf_{n}a_{n}\le\liminf_{n}b_{n} and lim supnanlim supnbn\limsup_{n}a_{n}\le\limsup_{n}b_{n}. In particular, if anMa_{n}\le M for every nn, then lim supnanM\limsup_{n}a_{n}\le M; and if ManM\le a_{n} for every nn, then Mlim infnanM\le\liminf_{n}a_{n}.

3. (Eventual bounds.) For every real ε>0\varepsilon>0 there is NNN\in\mathbb{N} such that lim infnanε<am\liminf_{n}a_{n}-\varepsilon<a_{m} for every mNm\ge N, and there is NNN'\in\mathbb{N} such that am<lim supnan+εa_{m}<\limsup_{n}a_{n}+\varepsilon for every mNm\ge N'.

4. (Extraction along the limit inferior.) For every real ε>0\varepsilon>0 there are natural numbers n1<n2<n3<n_{1}<n_{2}<n_{3}<\dots such that anj<lim infnan+εa_{n_{j}}<\liminf_{n}a_{n}+\varepsilon for every jNj\in\mathbb{N}.

5. (Convergence criterion.) The sequence (an)nN(a_{n})_{n\in\mathbb{N}} has limit aa if and only if lim infnan=a\liminf_{n}a_{n}=a and lim supnan=a\limsup_{n}a_{n}=a.

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