TheoremBase

A Lipschitz Function on an Open Interval is Differentiable Almost Everywhere

A Lipschitz real function on an open interval has a derivative at every point outside a Lebesgue null set, and that derivative is bounded in absolute value by the Lipschitz constant.

Statement

We work in the setting of Product Measures and Lebesgue Measure on ℝⁿ: Standing Notation and Background with the dimension 11, throughout identifying a point of R1\mathbb{R}^{1} with its single coordinate, so that R1\mathbb{R}^{1} and R\mathbb{R} are written interchangeably; under this convention the Euclidean norm of a point is its absolute value and dE(s,t)=∣s−t∣d_{E}(s,t)=|s-t|, by claim 1 of Properties of the Euclidean Norm on Rn\mathbb{R}^n: Square, Distance, Vanishing, Coordinate Bounds, Homogeneity, Triangle Inequalities and Expansion of a Square, so that the closed ball Bˉ(y,r)\bar{B}(y,r) is the closed interval with endpoints y−ry-r and y+ry+r. By Lebesgue Measure on Rn\mathbb{R}^n the measure λ1\lambda_{1} is the Lebesgue measure λ\lambda on the Borel σ\sigma-algebra of R\mathbb{R}; null has the meaning fixed in that setting, and Lipschitz is understood for the Euclidean distances.

Let I⊆RI\subseteq\mathbb{R} be a nonempty open interval, let L∈RL\in\mathbb{R} with 0≤L0\le L, and let g:I→Rg:I\to\mathbb{R} be Lipschitz with constant LL, that is

∣g(x)−g(y)∣≤L ∣x−y∣for all x,y∈I.|g(x)-g(y)|\le L\,|x-y|\qquad\text{for all }x,y\in I .

Let DD be the set of those x∈Ix\in I at which gg has a derivative g′(x)g'(x), a real number. Then the following hold.

1. (Almost everywhere differentiability) The set I∖DI\setminus D is null.

2. (Bound on the derivative) For every x∈Dx\in D one has ∣g′(x)∣≤L|g'(x)|\le L.

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