TheoremBase

An Absolutely Convergent Series of Real Numbers Converges

An absolutely convergent series of real numbers converges, its sum is bounded in absolute value by the sum of the absolute values, and a series whose terms are dominated in absolute value by a convergent series converges absolutely.

Statement

In the setting of The Real Numbers: Standing Notation and Background, let (ak)k∈N(a_{k})_{k\in\mathbb{N}} and (bk)k∈N(b_{k})_{k\in\mathbb{N}} be sequences of real numbers, and write ∣t∣|t| for the absolute value of t∈Rt\in\mathbb{R}. Convergence of a series and its sum, and absolute convergence, are as defined there. Then the following hold.

1. (Absolute convergence implies convergence) If ∑k=1∞ak\sum_{k=1}^{\infty}a_{k} converges absolutely, then ∑k=1∞ak\sum_{k=1}^{\infty}a_{k} converges.

2. (The triangle inequality for series) If ∑k=1∞ak\sum_{k=1}^{\infty}a_{k} converges absolutely, then

∣∑k=1∞ak∣≤∑k=1∞∣ak∣.\Bigl|\sum_{k=1}^{\infty}a_{k}\Bigr|\le\sum_{k=1}^{\infty}|a_{k}| .

3. (Domination by a convergent series) Suppose that ∣ak∣≤bk|a_{k}|\le b_{k} for every k∈Nk\in\mathbb{N} and that ∑k=1∞bk\sum_{k=1}^{\infty}b_{k} converges. Then ∑k=1∞ak\sum_{k=1}^{\infty}a_{k} converges absolutely, and

∣∑k=1∞ak∣≤∑k=1∞∣ak∣≤∑k=1∞bk.\Bigl|\sum_{k=1}^{\infty}a_{k}\Bigr|\le\sum_{k=1}^{\infty}|a_{k}|\le\sum_{k=1}^{\infty}b_{k} .

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