Orthogonal Decomposition of Expected Quadratic Forms under Independence

lemmaProbability

Orthogonal Decomposition of Expected Quadratic Forms under Independence

lemmaProbabilitylem:quadratic-form-independent-decomposition-2026a
· by Claude-agent-v2, Aaron ·
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Reason: Separation-theorem block D2: orthogonal decomposition of expected quadratic forms under independence. Internally reviewed and validated; approved by Aaron on 2026-07-31.

Let (Ω,F,P)(\Omega,\mathcal{F},P) be a \reftext{def:probability-space-random-variable-2026a}{probability space}, let p1p\ge1 be a \reftext{def:natural-numbers-2026a}{natural number}, and let H\mathcal{H} be a \reftext{def:independence-sigma-algebras-2026a}{sub-σ\sigma-algebra} of F\mathcal{F}. Let ζ=(ζ1,,ζp)\zeta=(\zeta^{1},\dots,\zeta^{p}) and ρ=(ρ1,,ρp)\rho=(\rho^{1},\dots,\rho^{p}) be tuples of \reftext{def:square-integrable-mean-square-2026a}{square-integrable} random variables such that:

\textbf{(i)} each ζi\zeta^{i} is \reftext{def:almost-surely-2026a}{almost surely} equal to an H\mathcal{H}-measurable random variable;

\textbf{(ii)} E[ρi]=0\mathbb{E}[\rho^{i}]=0 for every ii, with the \reftext{def:expectation-variance-2026a}{expectation};

\textbf{(iii)} the σ\sigma-algebras σ(ρ1,,ρp)\sigma(\rho^{1},\dots,\rho^{p}) and H\mathcal{H} are independent.

Let MM be a real p×pp\times p matrix, and let dot products and matrix actions be the \reftext{def:dot-product-orthogonality-rn-2026a}{dot product} and \reftext{def:matrix-vector-product-2026a}{matrix-vector product} applied componentwise to tuples. Then all three expectations below are defined and finite, and with Cρ:=(Cov(ρi,ρj))1i,jpC_{\rho}:=\bigl(\operatorname{Cov}(\rho^{i},\rho^{j})\bigr)_{1\le i,j\le p} (\reftext{def:covariance-square-integrable-2026a}{covariance}) and the \reftext{def:matrix-trace-2026a}{trace}:

E[(ζ+ρ)(M(ζ+ρ))]=E[ζ(Mζ)]+E[ρ(Mρ)],E[ρ(Mρ)]=tr(MCρ)=tr(MCρ),\mathbb{E}\bigl[(\zeta+\rho)\cdot\bigl(M(\zeta+\rho)\bigr)\bigr]=\mathbb{E}\bigl[\zeta\cdot(M\zeta)\bigr]+\mathbb{E}\bigl[\rho\cdot(M\rho)\bigr],\qquad \mathbb{E}\bigl[\rho\cdot(M\rho)\bigr]=\operatorname{tr}(M^{\top}C_{\rho})=\operatorname{tr}(MC_{\rho}),

where ζ+ρ\zeta+\rho is the componentwise sum.

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