TheoremBase

The Orthogonal Complement of a Unit Vector

Statement

Let VV together with ⟨⋅,⋅⟩\langle\cdot,\cdot\rangle be a complex inner product space with zero vector 0V0_{V}, and suppose that VV is finite-dimensional and V≠{0V}V\ne\{0_{V}\}; write n=dim⁡Vn=\dim V for its dimension.

Let u∈Vu\in V be a unit vector, let u~∈V1\tilde{u}\in V^{1} be the 11-tuple with component uu, and let U=span⁡(u~)U=\operatorname{span}(\tilde{u}) be its span, a linear subspace of VV by claim 1 of The Span of a Finite Family is the Smallest Subspace Containing It. Let W=U⊥W=U^{\perp} be the orthogonal complement of UU, a linear subspace of VV by The Orthogonal Complement of a Linear Subspace is a Linear Subspace. Then the following hold.

1. (Decomposition) For every x∈Vx\in V there is exactly one pair consisting of a complex number λ\lambda and a vector w∈Ww\in W with x=λu+wx=\lambda u+w; it satisfies λ=⟨u,x⟩\lambda=\langle u,x\rangle.

2. (Dimension one) If n=1n=1, then W={0V}W=\{0_{V}\}.

3. (Splitting off a unit vector) Suppose n=r+1n=r+1 for some natural number rr. Then W≠{0V}W\ne\{0_{V}\} and, with the inner product WW inherits by claim 3 of A Linear Subspace is a Vector Space and Inherits an Inner Product, there is an orthonormal basis f∈Wrf\in W^{r} of WW. Moreover the tuple e∈Vr+1e\in V^{r+1} with ek=fke_{k}=f_{k} for kk in the initial segment [r][r] and er+1=ue_{r+1}=u is an orthonormal basis of VV.

Proofs

Log in to submit a proof.

Loading...

Citations

Loading…

Dependencies

Loading…

Related

0 relations

Curated associations between results. These are editable and subjective — they do not replace the dependency graph, which is derived from the references in the text.

No relations recorded yet.

Comments

Log in to comment.

Loading…