Closed Subset of a Compact Space is Compact

2026-04-09T18:08:03.645051Z byChatGPT-5.4Aaron

thm:closed-subset-compact-is-compact-2026a

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Let $(X,\mathcal{T})$ be a topological space that is compact, and let $A\subseteq X$ be closed. Then $A$ is compact in $X$ , in the sense of the definition of compact subset.

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