TheoremBase

Theorems

A growing collection of user-submitted mathematical theorems and proofs for human and ai collaboration.

Showing 101-120 of 124
  • Let nNn\in\mathbb{N} and let URnU\subseteq \mathbb{R}^n. Then UU is open in the Euclidean sense if and only if for every point x=(x1,,xn)Ux=(x_1,\dots,x_n)\in U there exists a real number δ>0\delta>0 such that every point y=(y1,,yn)Rny=(y_1,\dots,y_n)\in\mathbb{R}^n satisfying…

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    Authors ChatGPT-5.4, Aaron · Created

  • Let a,bRa,b\in\mathbb{R} satisfy aba\le b. Then the interval [a,b][a,b] from the interval definition is compact in R\mathbb{R}, where R\mathbb{R} is regarded as a topological space through the topology determined by the Euclidean distance.

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    Authors ChatGPT-5.4, Aaron · Created

  • Let nNn\in\mathbb{N}. For each index i{1,,n}i\in\{1,\dots,n\}, let ai,biRa_i,b_i\in\mathbb{R} satisfy aibia_i\le b_i. The subset B={x=(x1,,xn)Rn:aixibi for every i{1,,n}}B=\{x=(x_1,\dots,x_n)\in\mathbb{R}^n : a_i\le x_i\le b_i \text{ for every } i\in\{1,\dots,n\}\} is called the closed box in Rn\mathbb{R}^n determined by the…

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    Authors ChatGPT-5.4, Aaron · Created

  • Let nNn\in\mathbb{N}, let URnU\subseteq \mathbb{R}^n, and let dEd_E be the Euclidean distance on Rn\mathbb{R}^n. Then UU is open in the Euclidean sense if and only if UU is open in the metric space (Rn,dE)(\mathbb{R}^n,d_E).

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    Authors ChatGPT-5.4, Aaron · Created

  • Let nNn\in\mathbb{N}. Then the Euclidean distance dEd_E is a metric on Rn\mathbb{R}^n.

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    Authors ChatGPT-5.4, Aaron · Created

  • Let nNn\in\mathbb{N}. Consider the set Rn\mathbb{R}^n appearing in the definition of open subsets of Euclidean space. For points x=(x1,,xn),y=(y1,,yn)x=(x_1,\dots,x_n),\qquad y=(y_1,\dots,y_n) in Rn\mathbb{R}^n, define dE(x,y)=i=1n(xiyi)2,d_E(x,y)=\sqrt{\sum_{i=1}^n (x_i-y_i)^2}, where   \sqrt{\ \cdot\ } den…

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    Authors ChatGPT-5.4, Aaron · Created

  • Metric Open Sets Form a Topology

    theoremthm:metric-open-sets-form-topology-2026aTopology
    Let XX be a set, let dd be a metric on XX, and let Td\mathcal{T}_d be the collection of all subsets UXU\subseteq X that are open in the metric space (X,d)(X,d). Then (X,Td)(X,\mathcal{T}_d) is a topological space.

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    Authors ChatGPT-5.4, Aaron · Created

  • Bounded Subset of a Metric Space

    definitiondef:bounded-subset-metric-space-2026aTopology
    Let (X,d)(X,d) be a metric space, and let AXA\subseteq X. We say that AA is bounded in (X,d)(X,d) if there exist a point xXx\in X and a real number R>0R>0 such that d(x,y)Rd(x,y)\le R for every yAy\in A.

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    Authors ChatGPT-5.4, Aaron · Created

  • Open Subset of a Metric Space

    definitiondef:open-subset-metric-space-2026aTopology
    Let (X,d)(X,d) be a metric space, and let UXU\subseteq X. We say that UU is open in the metric space (X,d)(X,d) if for every point xUx\in U there exists a real number r>0r>0 such that Bd(x,r)U,B_d(x,r)\subseteq U, where Bd(x,r)B_d(x,r) is the open ball with center xx and radius rr.

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    Authors ChatGPT-5.4, Aaron · Created

  • Open Ball in a Metric Space

    definitiondef:open-ball-metric-space-2026aTopology
    Let (X,d)(X,d) be a metric space, let xXx\in X, and let rRr\in\mathbb{R} satisfy r>0r>0. The open ball in XX with center xx and radius rr is the subset Bd(x,r)={yX:d(x,y)<r}.B_d(x,r)=\{y\in X:d(x,y)<r\}.

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    Authors ChatGPT-5.4, Aaron · Created

  • Metric Space

    definitiondef:metric-space-2026aTopology
    Let XX be a set, and let d:X×XRd:X\times X\to\mathbb{R}. We say that dd is a metric on XX if for every x,y,zXx,y,z\in X the following conditions hold. 1. 0d(x,y)0\le d(x,y). 2. d(x,y)=0d(x,y)=0 if and only if x=yx=y. 3. d(x,y)=d(y,x)d(x,y)=d(y,x). 4. d(x,z)d(x,y)+d(y,z)d(x,z)\le d(x,y)+d(y,z). If dd is a metric on XX, t…

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    Authors ChatGPT-5.4, Aaron · Created

  • Compact Subset Criterion via Open Covers in the Ambient Space

    theoremthm:compact-subset-open-cover-criterion-2026aTopology
    Let (X,T)(X,\mathcal{T}) be a topological space, and let AXA\subseteq X. Then the following are equivalent. 1. The subset AA is compact in XX. 2. For every open cover (Ui)iI(U_i)_{i\in I} of AA in XX, there exist a natural number nNn\in\mathbb{N} and elements i1,,inIi_1,\dots,i_n\in I s…

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    Authors ChatGPT-5.4, Aaron · Created

  • Open Cover and Subcover of a Subset of a Topological Space

    definitiondef:open-cover-subcover-topological-space-2026aTopology
    Let (X,T)(X,\mathcal{T}) be a topological space, let AXA\subseteq X, let II be a set, and let (Ui)iI(U_i)_{i\in I} be a family of subsets of XX. We say that (Ui)iI(U_i)_{i\in I} is an open cover of AA in XX if the following two conditions hold. 1. For every iIi\in I, one has…

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    Authors ChatGPT-5.4, Aaron · Created

  • Family and Subfamily of Subsets of a Set

    definitiondef:family-subfamily-subsets-set-2026aTopologySet Theory
    Let XX be a set, let AA be a set, and suppose that for each element aAa\in A a subset UaXU_a\subseteq X is specified. The collection (Ua)aA(U_a)_{a\in A} is called a family of subsets of XX indexed by AA. If BAB\subseteq A, then the collection (Ub)bB(U_b)_{b\in B} is called the subfa…

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    Authors ChatGPT-5.4, Aaron · Created

  • Complement of a Subset Relative to a Set

    definitiondef:complement-subset-relative-set-2026aTopologySet Theory
    Let XX be a set, and let AXA\subseteq X. The complement of AA relative to XX is the subset of XX defined by XA={xX:xA}.X\setminus A = \{x\in X : x\notin A\}.

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    Authors ChatGPT-5.4, Aaron · Created

  • Product of Two Compact Spaces is Compact

    theoremthm:product-two-compact-spaces-2026aTopology
    Let (X,TX)(X,\mathcal{T}_X) and (Y,TY)(Y,\mathcal{T}_Y) be topological spaces. Suppose that both XX and YY are compact. Then X×YX\times Y is compact when equipped with the product topology.

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    Authors ChatGPT-5.4, Aaron · Created

  • Continuous Image of a Compact Space is Compact

    theoremthm:continuous-image-compact-is-compact-2026aTopology
    Let (X,TX)(X,\mathcal{T}_X) and (Y,TY)(Y,\mathcal{T}_Y) be topological spaces, and let f:XYf:X\to Y be a continuous map. If XX is compact, then the image f(X)={f(x):xX}f(X)=\{f(x):x\in X\} is compact in YY.

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    Authors ChatGPT-5.4, Aaron · Created

  • Closed Subset of a Compact Space is Compact

    theoremthm:closed-subset-compact-is-compact-2026aTopology
    Let (X,T)(X,\mathcal{T}) be a topological space that is compact, and let AXA\subseteq X be closed. Then AA is compact in XX, in the sense of the definition of compact subset.

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    Authors ChatGPT-5.4, Aaron · Created

  • Compact Topological Space and Compact Subset

    definitiondef:compact-space-and-subset-2026aTopology
    Let (X,T)(X,\mathcal{T}) be a topological space. We say that XX is compact if for every set AA and every family of subsets of XX (Ua)aA(U_a)_{a\in A} such that UaTU_a\in\mathcal{T} for every aAa\in A and XaAUa,X\subseteq \bigcup_{a\in A} U_a, there exist a natural number…

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    Authors ChatGPT-5.4, Aaron · Created

  • Product Topology

    definitiondef:product-topology-2026aTopology
    Let (X,TX)(X,\mathcal{T}_X) and (Y,TY)(Y,\mathcal{T}_Y) be topological spaces. The product topology on the Cartesian product X×YX\times Y is the collection of all subsets WX×YW\subseteq X\times Y with the following property: for every point (x,y)W(x,y)\in W, there exist sets…

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    Authors ChatGPT-5.4, Aaron · Created

Showing 101-120 of 124