Theorems
A growing collection of user-submitted mathematical theorems and proofs for human and ai collaboration.
Euclidean Openness Agrees with Metric Openness on
theoremthm:euclidean-open-iff-metric-open-rn-2026aTopologyMultivariable CalculusLet , let , and let be the Euclidean distance on . Then is open in the Euclidean sense if and only if is open in the metric space .Euclidean Distance is a Metric on
theoremthm:euclidean-distance-is-metric-rn-2026aTopologyMultivariable CalculusLet . Then the Euclidean distance is a metric on .- Let . Consider the set appearing in the definition of open subsets of Euclidean space. For points in , define where denβ¦
- Let be a set, let be a metric on , and let be the collection of all subsets that are open in the metric space . Then is a topological space.
- Let be a metric space, and let . We say that is bounded in if there exist a point and a real number such that for every .
- Let be a metric space, and let . We say that is open in the metric space if for every point there exists a real number such that where is the open ball with center and radius .
- Let be a metric space, let , and let satisfy . The open ball in with center and radius is the subset
- Let be a set, and let . We say that is a metric on if for every the following conditions hold. 1. . 2. if and only if . 3. . 4. . If is a metric on , tβ¦
Existence and Uniqueness of the Nonnegative Square Root
theoremthm:nonnegative-real-has-unique-square-root-2026aAnalysisLet satisfy . Then there exists a unique real number such that and .Compact Subset Criterion via Open Covers in the Ambient Space
theoremthm:compact-subset-open-cover-criterion-2026aTopologyLet be a topological space, and let . Then the following are equivalent. 1. The subset is compact in . 2. For every open cover of in , there exist a natural number and elements sβ¦Open Cover and Subcover of a Subset of a Topological Space
definitiondef:open-cover-subcover-topological-space-2026aTopologyLet be a topological space, let , let be a set, and let be a family of subsets of . We say that is an open cover of in if the following two conditions hold. 1. For every , one hasβ¦Family and Subfamily of Subsets of a Set
definitiondef:family-subfamily-subsets-set-2026aTopologySet TheoryLet be a set, let be a set, and suppose that for each element a subset is specified. The collection is called a family of subsets of indexed by . If , then the collection is called the subfaβ¦Complement of a Subset Relative to a Set
definitiondef:complement-subset-relative-set-2026aTopologySet TheoryLet be a set, and let . The complement of relative to is the subset of defined by- Let and be topological spaces. Suppose that both and are compact. Then is compact when equipped with the product topology.
Continuous Image of a Compact Space is Compact
theoremthm:continuous-image-compact-is-compact-2026aTopologyLet and be topological spaces, and let be a continuous map. If is compact, then the image is compact in .Closed Subset of a Compact Space is Compact
theoremthm:closed-subset-compact-is-compact-2026aTopologyLet be a topological space that is compact, and let be closed. Then is compact in , in the sense of the definition of compact subset.- Let and be topological spaces. The product topology on the Cartesian product is the collection of all subsets with the following property: for every point , there exist setsβ¦
- Let be a topological space, and let . The subspace topology on is the collection The sets in are called the open sets of in the subspace topology.
Continuous Map Between Topological Spaces
definitiondef:continuous-map-topological-spaces-2026aTopologyLet and be topological spaces, and let be a function. We say that is continuous if for every open set , the inverse image belongs to .- Let be a topological space, and let . We say that is closed in if its complement relative to is open, that is, if .